Difference between revisions of "Genetic Code Assignment"

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(added grey box)
(reading frames)
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  5’-cgt atg cta  ata  cca  tgt tcc  gcg tat  aac cca  gcc gcc agt  tcc  gct ggc ggc att  tta-3’
 
  5’-cgt atg cta  ata  cca  tgt tcc  gcg tat  aac cca  gcc gcc agt  tcc  gct ggc ggc att  tta-3’
  3'-cga uac gau uau ggu aca agg cgc aua uug ggu cgg cgg uca agg cga ccg ccu uaa aau-5'
+
  3'-cga tac gat tat ggt aca agg cgc ata ttg ggt cgg cgg tca agg cga ccg cct taa aat-5'
 +
 
 +
:'''There are six possible reading frames in double-stranded DNA. Using the genetic code, translate all possible reading frames of this DNA sequence.'''
 +
+1 R-M-L-I-P-C-S-A-Y-N-P-A-A-S-S-A-G-G-I-L
 +
+2 V-C-STOP-Y-H-V-P-R-I-T-Q-P-P-V-P-L-A-A-F
 +
+3 Y-A-N-T-M-F-R-V-STOP-P-S-R-Q-F-R-W-R-H-F
 +
 
 +
-1 STOP-N-A-A-S-G-T-G-G-W-V-I-R-G-T-W-Y-STOP-H-T
 +
-2 K-M-P-P-A-E-L-A-A-G-L-Y-A-E-H-G-I-S-I
 +
-3 K-C-R-Q-R-N-W-R-L-G-Y-T-R-N-M-V-L-A-Y
  
'''There are six possible reading frames in double-stranded DNA. Using the genetic code, translate all possible reading frames of this DNA sequence, keeping in mind the following rules.'''
 
:In RNA, the T becomes a U, so everywhere you see a T in the sequence, read it as a U.
 
:The genetic code is read in the 5’ to 3’ direction.
 
:Use the single-letter abbreviations for the amino acids because that is what is commonly used by computer programs.
 
:Wiki Hint: if you start your line with a single space character, it will appear in the grey box surrounded by the dashed line as shown above.
 
 
:'''Which of the reading frames (if any) of the reading frames you translated is an open reading frame, i.e., does not contain a stop codon?'''
 
:'''Which of the reading frames (if any) of the reading frames you translated is an open reading frame, i.e., does not contain a stop codon?'''
:'''By convention, the top strand frames are called +1, +2, +3, reading 5' to 3' and the bottom strand frames are called -1, -2, -3, reading 5' to 3'.'''
+
 
 +
Frames +1, +3, -2, and -3

Revision as of 06:01, 6 September 2013

Write out the complementary strand of DNA below the strand shown and be sure to label the 5’ and 3’ ends of the complementary strand.

5’-cgt atg cta   ata  cca  tgt tcc  gcg tat   aac cca   gcc gcc agt  tcc  gct ggc ggc att  tta-3’
3'-cga tac gat tat ggt aca agg cgc ata ttg ggt cgg cgg tca agg cga ccg cct taa aat-5'
There are six possible reading frames in double-stranded DNA. Using the genetic code, translate all possible reading frames of this DNA sequence.
+1 R-M-L-I-P-C-S-A-Y-N-P-A-A-S-S-A-G-G-I-L
+2 V-C-STOP-Y-H-V-P-R-I-T-Q-P-P-V-P-L-A-A-F
+3 Y-A-N-T-M-F-R-V-STOP-P-S-R-Q-F-R-W-R-H-F
-1 STOP-N-A-A-S-G-T-G-G-W-V-I-R-G-T-W-Y-STOP-H-T
-2 K-M-P-P-A-E-L-A-A-G-L-Y-A-E-H-G-I-S-I
-3 K-C-R-Q-R-N-W-R-L-G-Y-T-R-N-M-V-L-A-Y
Which of the reading frames (if any) of the reading frames you translated is an open reading frame, i.e., does not contain a stop codon?

Frames +1, +3, -2, and -3

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